Largest String using lexicographic order (TC = O(x*n)) x= size of string ; n=total number of strings

-

 class largeststring{

    public static void main(String[] args) {

        String fruits[]={"apple","Mango","banana"};

        String largest=fruits[0];

        for(int i=1;i<fruits.length;i++){

            if(largest.compareToIgnoreCase(fruits[i]) < 0){
               
                largest=fruits[i];
            }


        }
        System.out.println(largest);
       

    }
}

Time Complexity :- O(x*n) x = size of largest string n= total nuymber of strings

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